find the equation of the straight line which passes through the point of intersection of the lines 4x + 3y + 1 is equal to 0 and 5 x-y is equal to 13 and perpendicular distance from origin is 3 unit
Answers
Answer:
5x - 2y = 3 - B
1×5 - 20% -154-5-4 ×4 20
y=-1
Sub y=-1 in ean
4x -3 Y = 1
4x + 3 = 1
4-1-3
4x = -2 |x = -1 Point 4
Slope of parallel line -3x +2y = -2:
Bring this equ in the
formula
form [y = mx +c], where
m is the slope, cis constant.
= 3x-2
2
| stope(m) = 3/ 2
= 3.
F3 x + 3
2
x+ 3
목x -y + 1
2
2XC-2Y+2=0
eqn
2
2
Slopes of parallel lines. are equal. 3 Egn of line : (=/1-1) m = ²2/12/2
님-닝, = m (xc-201) (formula) (1) 홀 (a - (1)
CLOSE
2:54 PM | 89.9KB/s ② 0
x-2Y+2=0
Step-by-step explanation:
please make it a brainliest answer.
Answer:
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