Question

find the equation of the straight line which passes through (1,3) and makes an angle of 45° with the line x-3y+4=0
please solve and send photo of solution

Answer 1

Answer:

y = 3*x

Step-by-step explanation:

slope-intercept form:

y = m*x + b ------(1)

where, m is the slope of the line

b is the y-intercept when x=0, y=b

Given point (1,3)

(1) becomes,

3 = m*1 + b

3 = m + b ------(2)

Plotting x-3y+4=0 in the desmos(graphing tool) and looking for a line that makes an angle of 45° with it, we found that m=3

(2) becomes,

3 = 3 + b

b = 0 (passes through the origin)

Finally, we have our straight line y = 3*x which makes an angle of 45° with x-3y+4=0

The image attached is the "desmos" graphing tool.