find the equation of the straight line whose angle of inclination is 45° and passing through the origin
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Answer:
Slope of the line, m=tanθ
=tan45
o
=1
y-intercept is c=
5
2
By the slope-intercept form, the equation of the straight line is
y=mx+c
=x+
5
2
⇒y=
5
5x+2
∴ The equation of the straight line is 5x−5y+2=0
Step-by-step explanation:
8 = 45° ∴ m = tan 8 = tan 45° = 1 ∴ The equation of straight line will be y = mx i.e y = (1)x or Y = x or x-y = 0
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