Question

find the equation of the straight line whose x intercept is 5 and y intercept is 4​

Answer 1

Answer:

Since the x intercept of the line is 4 and it's y intercept is -3 the intercept form of the eqn.of the line is x/a + y/b = 1 where a,b are it's x intercept and y intercept respectively.

So eqn.of the line is x/4 + y/(-3) = 1

× by 12 we get 3x - 4y = 12

Answer 2

Answer:

4x+5y-20 =0

Step-by-step explanation:

process 1:

x intercept is 5 ,  the point is (5,0)

y intercept is 4​ , the point is (0,4)

the equation will be $\frac{x-0}{y-4}=\frac{5-0}{0-4}$

► -4x =5y -20

►4x+5y-20 =0

process 2:

x intercept is 5 and y intercept is 4​

so,the equation , $\frac{x}{5}+\frac{y}{4} = 1$

►$\frac{4x+5y}{20} =1$

4x+5y -20 =0