find the equation of the straight lines passing through the point (-10,4) and making an angle tita with the line x-2y=10 such that tan tita =2
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3
So lines
y−4=
4
−3
(x−(−10))
4(y−4)=−3x−30
3x+4y+14=0
and
y−4=∞(x−(−10))
∞
y−4
=x+10
0=x+10
x+10=0
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1
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