Question

find the equation of the straight lines passing through the point (1, 2) and making an angle of 60° with the line √3x+y+2=0​

Answer 1

Answer:

y = 2 or y = √3x + 2-√3 y=

Step-by-step explanation:

Making angle 60° with √3x +y +2=0

=> y = -√3x - 2

Slope = -√3

Let say sloe of other line = m

=> Tan 60° = |(m - (-√3)) / (1 + m( -√3))| => √3 = 1 (m + √3)/(1- m√3) |

squaring both sides

=> 3 = (m² + 3 + 2√3m) / (1+3m² - 2m-√3) => 3 + 9m² - 6m-√3 = m² + 3 + 2√3m

=> 8m² - 8m √3 = 0

=> 8m(m -√3)= 0

m = 0 or m = √3

y = c or y = √3x + c

passed through 1, 2

=> y = 2 or 2 = √3+ c => c=2-√3

=> y = √3x + 2-√3