Question

find the equation of the tangent and Normal to the circle x square +Y square - 6x - 3y -2 = 0 at ( 2,-2).​

Answer 1

I think your question is wrong

Answer 2

Answer:

first calculate dy/dx at(-2,2)

dy/dx=(2x-6)/(3-2y)

dy/dx=-2/7

equation of tangent is (x-2)=dy/dx(y+2)

equation of normal is (x-2)=-1/dy/dx(y+2)