Question

Find the equation of the tangent at ( 0 , 2) to the circle with equation
(x + 2)2 + (y + 1)2 = 13 Can anyone help?

Answer 1

Answer:

(-2 , -1) : center of circle

m = (2 - -1) / (0 - -2) = 3 / 2 : slope of line through the center and the point of tangency (0 , 2)

The line through the center and the point of tangency (0 , 2) is perpendicular to the tangent.

M = -2 / 3 : slope of tangent

y = -(2/3)x + 2 : equation of tangent given its slope and point (0 , 2).

Hope it'll help you..