Question

Find the equation of the tangent line to the curve y = x^2 at x = 1.

Answer 1

$y = x {}^{2}$

slope of tangent

$\frac{dy}{dx} = 2x$

at X = 1

dy /dx = 2

put X = 1 in curve equation and get y = 1

then equation of tangent by two point form .

2x -y -1 = 0

I hope it help you ❤️

Answer 2

Answer:

differentiate wrt x

get slope

and then put in straight line equation