Find the equation of the tangent line to the curvey y= √(5x - 3)-2 which is parallel to the
line 4x - 2y + 3 = 0
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if we differentiate the equation of curve we get slope of tangent at (x,y) y! = 32√(()3x - 2) but tangent is parallel to line 4x - 2y + 5 = 0there fore ...
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