Question

find the equation of the tangent to the circle x²+y²×6x-6y-2=0​

Answer 1

Answer:

Let y = mx + c be tangent of circle .

It's centre is (3 , 3) , radius = 4

Perpendicular from centre to the tangent must be equal to radius

Line y - mx - c = 0 , point =( 3,3 )

Use formula

$\frac{ |3 - 3m + c| }{ \sqrt{1 + {m}^{2} } } = 4 \\ \\ (3 - 3m + c) {}^{2} = 16(1 - {m}^{2} )$