find the equation of the tangent to the curve y = 9x² - 12x + 7 which is parallel to the x-axis
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Since,the line is parallel to the x-axis.So, therefore it's slope (m) will be zero.
We have to solve and find its derivative first and then set it equals to zero where the slope is zero.
=> let the f(x) = 9x²-12x+7
=>f'(x)= 9*2x-12(1)
=>f'(x)= 18x-12
=> f'(x) =0
=> 18x-12=0
=> 6(3x-2)=0
=>3x-2=0
=>3x=2
x= 2/3
Equation of line when tangent is given:
Since m(slope) is zero so,our equation becomes
=> y-yo= m(x-xo)
=>y-yo= 0(x-xo)
=>y-yo=0
y=yo
Equation of the tangent = y-yo
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