Math, asked by lindiweshoko, 2 months ago

find the equation of the target of the curve y=x^2-6x+1 at (2;2)

Answers

Answered by veerpalv989
0

y=x+4/x2

y=1+-2.4/x2 =0

1-8/x3=0

x3= 8

x=2,y=+4/4=3

Similar questions