Question

find the equation of the the circle with centre at ( -3,-2 ) and r = 6​

Answer 1

$\large{\underline{\underline{\mathfrak{\green{\sf{QUESTION:-}}}}}}$.

• find the equation of the the circle with centre at ( -3,-2 ) and r = 6...?

$\large{\underline{\underline{\mathfrak{\red{\sf{SOLUTION:-}}}}}}$.

$\large{\underline{\underline{\mathfrak{\bf{Given\:Here:-}}}}}$.

• Centre of circle (-3,-2,)

• and , radius r = 6.

$\large{\underline{\underline{\mathfrak{\sf{Find\:Here:-}}}}}$.

• Equation of Circle

$\large{\underline{\underline{\mathfrak{\sf{Explanation:-}}}}}$.

we know that ,

Equation of circle with centre (h,k) and radius r

$\large{\boxed{\boxed{\:(x-h)^2\:+\:(y-k)^2\:=\:r^2}}}$

Where, h = -3, k = -2 and, r = 6 ,

$\implies\:\left\{x-(-3)\right\}^2\:+\:\left\{y-(-2)\right\}^2\:=\:(6)^2$

$\implies\:(x+3)^2\:+\:(y+2)^2\:=\:36$

$\implies\:(x^2+y^2+6x+4y+13)\:=\:36$

$\large{\boxed{\boxed{\:(x^2+y^2+6x+4y-23)\:=\:0}}}$

___________________

Answer 2

Answer:

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