Question

find the equation of the trajectory of the projected fired in the horizontal direction what is the velocity of the projectile at any point on the trajectory​

Answer 1

Answer:

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Explanation:

The range of an object, given the initial launch angle and initial velocity is found with: R=v2isin2θig R = v i 2 sin ⁡ 2 θ i g .

Answer 2

Answer:

Equation of Trajectory= Parabolic

Explanation:

Let us consider a projectile projected on ground from a height 'h' with a velocity of 'u' m/s.

Now, for displacement in 'x-axis', we have;

               S = ut + 1/2 at²

               x = ut  ----(1)  ( since a= 0 in x-axis )

Also, for displacement in 'y-axis', we have;

               S = ut + 1/2 at²

               y = 1/2 gt²  ___(2) ( since u= 0 for y-axis )

From (1) ;

              t = x/u _______ (3)

Putting (3) in (2), we obtain;

               y = 1/2 g (x/u)²

               y = 1/2 g x²/u²

So,          y is proportional to x² which clearly is a parabolic equation.

Hence, the equation of trajectory and path is parabolic.

Hope it helps ;-))