Question

find the equation passing Straight line through (-2,4) and making nonzero intersegots whose sum is zero​

Answer 1

Answer:

Here given that the sum of intercepts is zero. Therefore, $a + b = 0 \Rightarrow a = - b$. $y - x = 6$ which is the equation of the straight line passing through $\left( { - 2,4} \right)$ and making non-zero intercepts whose sum is zero.

Answer 2

Answer:

We know that the equation of the straight line making non-zero intercepts a and b on Xaxis and Yaxis respectively is given by x/a+y/b=1⋯⋯(1).

Here given that the sum of intercepts is zero. Therefore, a+b=0⇒a=−b.

Now we are going to put a=−b in the equation (1). Therefore,

−x/b+y/b=1⇒y−x/b=1⇒y−x=b⋯⋯(2)

Also given that the line is passing through the point (−2,4). Now we will put x=−2 and y=4 in the equation (2). Therefore,

4−(−2)=b⇒4+2=b⇒b=6

Now we will put the value of b in the equation (2) to find the required line. Therefore, we get

y−x=6 which is the equation of the straight line passing through (−2,4) and making non-zero intercepts whose sum is zero.

Step-by-step explanation: