Question

find the equation passing through the point of intersection of lines2x+3y=13,5x-y-7=0and perpendicular to the line 3x-2y+7=0

Answer 1

first of all find intersection point of 2lines suppose it comes to be a and b
Now line is perpendicular to the given line... in that case multiplication off slope =-1 so eqn of line becomes
-3x-2y+c=0
Now put the intersection point in this eqn and find value of c