Question

find the equation that formed by squaring each root of the equation x^2+2x-3 = 0
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Answer 1

Step-by-step explanation:

${x}^{2} + 2x - 3 = 0$

${x}^{2} + (3 - 1)x - 3 = 0$

${x}^{2} + 3x - x - 3 = 0$

$x(x + 3) - 1(x + 3) = 0$

$(x + 3)(x - 1) = 0$

either, x+3=0. or, x-1=0

x= -3. x= 1

The root of the equation is 1 and -3