Question

find the equation the line which passes through the midpoint of the line joining (2,-3) and (6,-7) and is parallel to 3x+4y+5=0​

Answer 1

Answer:

3x+4y-1=0

Step-by-step explanation:

We know that mid point of (x1,y1) and x2,y2) is ((x1+x2)/2 , (y1+y2)/2)

Mid point of (2,-3) and (6,-7) = (8/2,-10/2) = (4,-5)

Given, the required line is parallel to 3x+4y+5=0 (of the form ax+by+c=0)

therefore, slope of given line = slope of required line =m= -a/b = -3/4

now,

we know that equation of line is (y-y1)=m(x-x1)

substituting the values, 4(y-4)= -3(x-(-5))

4y-16=-3x-15

3x+4y-1=0 is the equation of the required line

hope this helps :)

Answer 2

Answer:

using above image or others information

Step-by-step explanation:

you can find a solution