Question

find the equation to the locus of the point which is at a distance of 2units from(2,3)​

Answer 1

Answer:

Step-by-step explanation:

Let the point be P(h,k) , the fixed point be Q(−2,3) and PQ=5

PQ=

(h+2)  

2

+(k−3)  

2

 

​

 

(PQ)  

2

=(h+2)  

2

+(k−3)  

2

 

=>25=(h+2)  

2

+(k−3)  

2

 

For locus replace h  

​

x,k  

​

y=>(x+2)  

2

+(y−3)  

2

=25 is a circle with radius 5 and centre (−2,3)