Question

Find the equation to the straight line which passes through point of intersection of line the lines 3x+4y-1=0and 5x+8y-3=0 and is perpendicular to line 4x-2y+3=0

Answer 1

Answer:

Step-by-step explanation:

P dilip_k

Mar 27, 2017

Let equation of any straight line passing through the point of intersection of two given straight line be

k

(

7

x

−

3

y

−

19

)

+

(

3

x

+

2

y

+

5

)

=

0

⇒

(

7

k

+

3

)

x

+

(

2

−

3

k

)

y

+

(

5

−

19

k

)

=

0

.

.

[

1

]

If the straight be parallel to the straight line

2

x

−

y

+

1

=

0

then

7

k

+

3

2

=

2

−

3

k

−

1

⇒

7

k

+

3

=

−

4

+

6

k

⇒

k

=

−

7

Inserting the value of k in [1]

(

7

⋅

(

−

7

)

+

3

)

x

+

(

2

−

3

⋅

(

−

7

)

)

y

+

(

5

−

19

⋅

(

−

7

)

)

=

0

⇒

−

46

x

+

23

y

+

138

=

0

⇒

2

x

−

y

−

6

=

0

This is the equation of the required straight line.