Question

Find the equation to the tangent to the circle x2+y2=4 which :-

(a) is parallel to the straight line y=2x+3.

(b) is perpendicular to the straight line y=2x+3

(C) passes through (5,0).​

Answer 1

Answer:

Find the equation to the tangent to the circle x^2 + y^2 = a^2 which(i) is parallel to the straight line y = mx + c ,(ii) is perpendicular to the straight ...

(i) Let the straight line be y = mx + c1 Since it is tangent to the circle x^2 + y^2 = a^2 So, a = |0 + 0 - c1|√(1 + m^2) c1 = a√((1 + m^2))