Question

find the equation to the tangent to the curve y=f(x)at p(x,y)​

Answer 1

Answer:

(y−y1)=f′(x1)

y−y1=f′(x1)(x−x1)

y=0,f′(x1)−y=x−x1

⇒x=x1=f′(x1)y1

A=(x1−f′(x1)y1,0)

x=0,y−y1=f′(x1)⋅(−x1)

⇒y=y1−x1f′(x1)

B=(0,y