Question

find the equation which has a solution of (-3,4)​

Answer 1

Step-by-step explanation:

y=mx+c

or use (y-y1)=m(x-x)

(y-4)=1(x+3)

y-4-x-3=0

-x-3-4=-y

-x-7+y

x+7-y=0

x-y+7=0 is the answer of this

Answer 2

Answer:

$x {}^{2} - ( - 3 + 4)x + ( - 12 ) = 0$

$x {}^{2} - x - 12 = 0$

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