Math, asked by poornima95, 5 hours ago

find the equation which has infinately many solutions 2x+3y=2(k+2)x+(2k-1)​

Answers

Answered by 38031kb
1

Answer:

2x+3y= 2(k+2)x+(2k-1)

==> we have to follow the

a1/a2 = b1/b2 = c1/c2 method

a1 = 2 a2 = 3 a3 = 7

b1 = k + 1 b2 = 2k - 1 b3 = 4k + 1

2/K+1 = 3/2k-1 = 7/4k+1

2/k + 1 = 3/2k - 1

4k - 2 = 3k + 3

k = 5

Therefore, the value of k is 5.

hope this helps you

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