find the equation which has infinately many solutions 2x+3y=2(k+2)x+(2k-1)
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Answer:
2x+3y= 2(k+2)x+(2k-1)
==> we have to follow the
a1/a2 = b1/b2 = c1/c2 method
a1 = 2 a2 = 3 a3 = 7
b1 = k + 1 b2 = 2k - 1 b3 = 4k + 1
2/K+1 = 3/2k-1 = 7/4k+1
2/k + 1 = 3/2k - 1
4k - 2 = 3k + 3
k = 5
Therefore, the value of k is 5.
hope this helps you
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