Math, asked by Blold, 6 months ago

Find the equation whose roots are 1/3 and -7/2

Answers

Answered by asmanashutosh
3

Answer:

(x-1/3)(x-(-7/2))

(x-1/3)(x+7/2)

x^2+7/2x-1/3x-7/6

x^2+19/6x-7/6

.........Asman

Answered by anjumanyasmin
0

From the given question the correct answer is :

the equation whose roots are 1/3 and -7/2 is (x-1/3)(x-(-7/2))

solution:

=(x-1/3)(x-(-7/2))

=(x-1/3)(x+7/2)

=x^2+7/2x-1/3x-7/6

=x^2+19/6x-7/6

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