Find the equation whose roots are 1/3 and -7/2
Answers
Answered by
3
Answer:
(x-1/3)(x-(-7/2))
(x-1/3)(x+7/2)
x^2+7/2x-1/3x-7/6
x^2+19/6x-7/6
.........Asman
Answered by
0
From the given question the correct answer is :
the equation whose roots are 1/3 and -7/2 is (x-1/3)(x-(-7/2))
solution:
=(x-1/3)(x-(-7/2))
=(x-1/3)(x+7/2)
=x^2+7/2x-1/3x-7/6
=x^2+19/6x-7/6
Similar questions
Math,
3 months ago
Business Studies,
3 months ago
Social Sciences,
6 months ago
Science,
6 months ago
Math,
10 months ago