Math, asked by krishanthraya, 13 days ago

Find the equation whose roots are the squares of the roots of x* + ax + bx² + cx + d = 0 and if a,B,y and s are the roots, find the values of i) Σα' i) Σαβ iii) Σαβγό​

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Answers

Answered by bharathivenkatg6
0

Answer:

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Step-by-step explanation:

Let α,β,γ be the roots of x3−ax2+bx−1=0, then

S1=α+β+γ=a

S2=αβ+αγ+βγ=b

S3=αβγ=1

Then α2+β2+γ2=(α+β+γ)2−2(αβ+αγ+βγ)=a2−2b

α2β2+α2γ2+β2γ2=(αβ+αγ+βγ)2−2αβγ(α+β+γ)=b2−2a

α2β2γ2=(αβγ)2=1

Hence, equation whose roots is α2,β2,γ2 is

x3−x

Answered by dorinangelinathomas
0

Answer:

Let α,β,γ be the roots of x

3

−ax

2

+bx−1=0, then

S

1

=α+β+γ=a

S

2

=αβ+αγ+βγ=b

S

3

=αβγ=1

Then α

2

2

2

=(α+β+γ)

2

−2(αβ+αγ+βγ)=a

2

−2b

α

2

β

2

2

γ

2

2

γ

2

=(αβ+αγ+βγ)

2

−2αβγ(α+β+γ)=b

2

−2a

α

2

β

2

γ

2

=(αβγ)

2

=1

Hence, equation whose roots is α

2

2

2

is

x

3

−x

2

(a

2

−2b)+x(b

2

−2a)−1=0

As both the equations is identical then

(a

2

−2b)=ua and (b

2

−2a)=vb

Hence, a=b=0; a=b=3 and a+b=−1

From a=b=3 and a+b=−1

ab=2

Therefore, option (B),(C) and (D) are true.

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