Question

Find the equations of straight lines which
nes which passes through (-3, 2) and is perpendicular to
-axis and is parallel to x axis respectively.
​

Answer 1

Answer:

(x=2) is the answer...

The line graph of eq.ⁿ, x=2 is ⟂ to x-axis and passes through the point with coordinates, (–3, 2)

Answer 2

Answer:

We have a formula to find the equation of a line passing through a point:-

y-y1=m(x-x1)

x1 and y1 are the x and y coordinates of a point through which the line passes . and m is the slope of the line.

The above line is perpendicular to y-axis.

So , again we have an equation:

m1*m2=-1

m2 = equation of the perpendicular line(here y-axis)

slope of y-axis = 1/0

m1=0

Therefore , equation of the line :

y-2=0*(x-(-3))

y-2=0

y=2 is the required equation of the line passing through (-3,2).

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