Question

Find the equations of the diagonals of a rectangle whose sides are x = -1,x= 2
y = -2 and y = 6.
Please Only tell correct Answer it's very urgent​

Answer 1

Answer:

$8x + 3y = 10 \\ 8x - 3y = - 2$

Step-by-step explanation:

POINTS OR VERTICES OF RECTANGLE ARE

(2 , - 2)

(2 , 6)

(-1 , 6)

(-1 , -2)

$equation \: of \: one \: diagonal \\ y + 2 = \frac{6 + 2}{2 + 1} (x + 1) \\ \\ 3(y + 2) = 8(x + 1) \\ \\ 3y + 6 = 8x + 8 \\ \\ or \: \: \: 8x - 3y = - 2 \\ \\ \\ \\ equation \: of \: other \: diagoal \\ y + 2 = \frac{6 + 2}{1 - 2} (x - 2) \\ \\ - 3(y + 2) = 8(x - 2) \\ \\ - 3y - 6 = 8x - 16 \\ \\ 8x + 3y = 10$