Find the equations of the diagonals of the parallelogram formed by the lines ax + by = 0,
ax + by + c =0, Ix + my = 0 and lx + my +n=0. What is the condition that this will be
a rhombus?
Answers
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3
Answer:
am=/ bl
Step-by-step explanation:
The given equations are ax+by=c
or ax+by−c=0 and
lx+my=n
or lx+my−n=0.
The equations have a unique solution.
So, a2a1=b2b1
Here a1=a,a2=l,b1=b,b2=m,c1=−c,c2=−n
∴a2a1=la,b2b1=mb.
∴la=mb
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