Find the equations of the line joining the points
A (1, 1) and B (2,3)
Answers
Answer:
x - 2y + 1 = 0
Step-by-step explanation:
two point slope form
y-y1 = (y2 - y1 )/(x2-x1) × x - x1
y - 1 = 2-1 / 3-1 × (×-1)
y-1 = 1/ 2 ×( x-1)
2y - 2 = x -1
× - 2y +1 =0
Answer:
The equation for line joining two points
(
x
1
,
y
1
)
and
(
x
2
,
y
2
)
is given by
y
−
y
1
y
2
−
y
1
=
x
−
x
1
x
2
−
x
1
and for given points it is
y
=
1
3
x
+
11
3
Explanation:
Let the slope intercept form of equation be
y
=
m
x
+
c
here we do not know the slope
m
and
y
-intercept
c
What we know is that this passes through the two coordinate pairs, say
(
x
1
,
y
1
)
and
(
x
2
,
y
2
)
.
As such we have three equations
y
=
m
x
+
c
......(1)
y
1
=
m
x
1
+
c
......(2) and
y
2
=
m
x
2
+
c
......(3)
Now using these let us eliminate
m
and
c
subtracting (2) from (1), we get
(
y
−
y
1
)
=
m
(
x
−
x
1
)
......(4)
and subtracting (2) from (3), we get
(
y
−
2
−
y
1
)
=
m
(
x
2
−
x
1
)
......(5
