Find the equations of the lines which pass through (4, 5) and make equal angles with
the lines 5x – 12y + 6 = 0 and 3x = 4y + 7.
Answers
Answered by
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Step-by-step explanation:
Let the Slope of line be m
Now, slope of other lines are
4
3
,
5
12
The Slope is Equally inclined so it must lie between these slopes
such that
4
3
<m<
5
12
As it is equally inclined so angle between the line and the two given line must be same
⇒θ
1
=θ
2
⇒tanθ
1
=tanθ
2
⇒
1+
5
12
m
5
12
−m
=
1+
4
3
m
m−
4
3
⇒63m
2
−32m−63=0
⇒m=
2∗63
32±
32
2
+4∗63∗63
⇒m=
9
−7
,
7
9
Now, Equation of line as it passes through (4,5) will be
y−5=m(x−4)
Putting the obtained values of m in above Equation we get
9x−7y=1
7x+9y=73
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