Find the equations of the medians of the triangle whose vertices are (1,5), (-2,3) and
(0, -4)
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Answer:
Let the altitudes be, AM,BN and CO respectively
Given, A(2,−2),B(1,1),C(−1,0)
Slope of AM= -1 / Slope of BC
=−1(
0−1
−1−1
)=−2
(y+2)=−2(x−2.A(2,-2)
2x+y=2 is the equation of altitude AM.
Slope of BN= -1 / Slope of AC
=−1(
0+2
−1−2
)=
2
3
(y−1)=
2
3
(x−1).B(1,1)
3x−2y=1 is the equation of altitude BN.
Slope of CO= -1 / Slope of AB
=−1(
1+2
1−2
)=
3
1
(y−0)=
3
1
(x+1)C(-1,0)
3y−x=1 is the equation of altitude CO.
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