Question

Find the equations of the straight lines in the symmetric form, given the slope and a point on the line in each part of the question
(ii). -1/√3,(-2,0)​

Answer 1

We have to find the equation of straight line in the symmetric form , given the slope and a point on the line, -1/√3 , (-2,0).

To find : the equation of line in the symmetric form.

solution : first write equation of straight line using , y - y₁ = m(x - x₁)

Here m = -1/√3 and (x₁ , y₁) = (-2, 0)

so, y - 0 = -1/√3 (x + 2)

⇒√3y + (x + 2) = 0

⇒√3y + x + 2 = 0

⇒x + √3y = -2

⇒x/(-2) + y/(-2/√3) = 1

We know equation of straight line in symmetric form is given by, x/a + y/b = 1

Therefore, required line is x/(-2) + y/(-2/√3) = 1