Question

Find the equeation of line making an angle of 60 with positive x-axis and intercept y at 10

Answer 1

See the attached file
not sure ans is rit

Answer 2

Answer:

y= root3x- root3+ 2

Step-by-step explanation:

Theta=60°

Slope,m= tan theta= tan 60°= root3

Line passes through the point (1,2)

Required equation of line is

y-y'=m(x-x')

y-2= root3x- root3

y=root3x-root3+2

HOPE IT HELPS :)