Question

Find the equialent resistance across the two ends A and B of the following circuit. (3)

Answer 1

Answer:

Here is your answer .

Step-by-step explanation:

 According to diagram,

 The two resistors of 2Ω in the upper side are in series because there is a same current flowing in it .

So,

 R₁= 2Ω + 2Ω = 4Ω

Now R₁ and resistor of 4Ω are in parallel .

So,

R₂=4 ₓ 4/ 4+4 = 2Ω

Now,

The two resistors of 1Ω and R₂ are in series .

So,

R₃= 1Ω + 1Ω + 2Ω = 4Ω

Furtherly,

 The two resistors of 2Ω are in series.

So,

  R₄=2Ω + 2Ω = 4Ω

At last the equivalent resistance in the circuit is that ,

 R₄ and R₃ are in parallel .

So,

  R = 4 × 4 / 4+ 4 = 2Ω .

Hence , the equivalent resistance is 2Ω .

Hope it helps you .

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