Question

Find the equilibrium constant at 298 K for the reaction,

2 Cu (aq) +2ln (aq) ->3Cu (aq) +ln (aq)c + + + + + +

Given that:

2 3 2

0 0 0

Cu |Cu ln |ln ln |ln E 0.15 V, E 0.42 V, E 0.40V​

Answer 1

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for a chemical reaction

$\\ aA+bB \: \longrightarrow \text{cC+dD}$

equilibrium constant given by

$\\ k _ {eq}\: = \: log( \frac{ {c}^{c} + {d}^{d} }{ {a}^{a} + {b}^{b}} )$

and nearst equation can be written as

$\\ E = E_{\circ} - \frac{0.6}{n} \times log(k _ {eq}) \:$

• put values we get equilibrium constant
• hope it helps