Question

Find the equilibrium constant for below
reaction at 298 K temperature.
2NOCIO) = 2NO(g) + Cl2(g)
[AH° = 18.4512 Kcal, AS° = 29.16 Cal]​

Answer 1

Answer:

Explanation:

ΔH  

o

=77.2kJ/mol×1000J/kJ=77200J/mol

Using the relation

ΔG  

o

=ΔH  

o

−TΔS  

o

 

ΔG  

o

=77200J/mol−(298K×122J/mol/K)

ΔG  

o

=40844Jmol  

−1

 

Let the equilibrium constant be K  

c

​  

, we know that

ΔG  

o

=−2.303RTlogK  

c

o

​  

 

or logK  

c

o

​  

=−  

2.303RT

ΔG  

o

 

​  

 

logK  

c

o

​  

=−  

2.303×8.314J/mol/K×298K

40844J/mol

​  

=−7.158

K  

c

o

​  

=6.95×10  

−8

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