Question

find the equivalence resistance....​

Answer 1

Answer:

Here AC and BC AR in series and AB are in parallal to this

So R¹=1Ω,R²=1Ω ,R³=Ω

Let Rp be the total resistance of parallal combinations of resistances

Rp= (R¹+R²)-¹

Rp=(1+1)-¹

Rp=(2)-¹⇨1/2⇨0.5Ω

And Now toal resistance if the circuit is

Rp+R³⇨(0.5+2)Ω

Rt⇨2.5Ω

Answer 2

Answer:

1

Explanation:

at point A current divide and we know that whene current divides then they are in parll.so1and2are parlland 1and1are in series .oin series 1+1=2and 2and 2are parallel so 1/rnet=1/2+1/2=1