Question

Find the equivalent fraction of 3 / 5 having

(a) denominator 20

(b) numerator 9

(c) denominator 30

(d) numerator 27​

Answer 1

Answer :-

(a) We require denominator 20.

Let X be the numerator of the fractions.

∴ X / 20 = 3 / 5

5 × X = 20 × 3

X = (20 × 3) / 5

= 12

Therefore the required fraction is 12 / 20.

(b) We require numerator 9.

Let N be the denominator of the fractions

∴ 9 / N = 3 / 5

3 × N = 9 × 5

N = (9 × 5) / 3

= 15

Therefore the required fraction is 9 / 15.

(c) We require denominator 30

Let D be the numerator of the fraction

∴ D / 30 = 3 / 5

5 × D = 3 × 30

D = (3 × 30) / 5

= 18

Therefore the required fraction is 18 / 30.

(d) We require numerator 27

Let B be the denominator of the fraction

∴ 27 / B = 3 / 5

3 × B = 5 × 27

B = (5 × 27) / 3

= 45

Therefore the required fraction is 27 / 45.

NOTE :-

You can take any alphabet or symbol for numerator when you are solving the question.

Answer 2

Therefore the required fraction is 12 / 20

(b) We require numerator 9

Let N be the denominator of the fractions

∴ 9 / N = 3 / 5

3 × N = 9 × 5

N = (9 × 5) / 3

= 15

Therefore the required fraction is 9 / 15

(c) We require denominator 30

Let D be the numerator of the fraction

∴ D / 30 = 3 / 5

5 × D = 3 × 30

D = (3 × 30) / 5

= 18

Therefore the required fraction is 18 / 30

(d) We require numerator 27

Let N be the denominator of the fraction

∴ 27 / N = 3 / 5

3 × N = 5 × 27

N = (5 × 27) / 3

= 45

Therefore the required fraction is 27 / 45