Question

find the equivalent fraction of 7/9 having
a) numerator 56
b) denominator 108
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Answer 1

Given:-

• find the equivalent fraction of 7/9 having
• find the equivalent fraction of 7/9 havinga) numerator 56
• find the equivalent fraction of 7/9 havinga) numerator 56b) denominator 108

To find:-

• Equivalent fraction of 7/9 with numerator 56.

Solution:-

• $= > 56 \div numerator \\ \\ \\ = > 56 \div 7 \\ \\ \\ = > 8 \\ \\ \\ now \: multiply \: quotient \: 8 \: with \: both \: numerator \\ and \: denominator. \\ \\ \\ = > \frac{7 \times 8}{9 \times 8} \\ \\ \\ = > \frac{56}{72}$

• :.The fraction is 56/72

Varifying:-

• $= > devide \: both \: numerator \: and \: denominator \: by \: 8$
• $= > \frac{56 \div 8}{72 \div 8} = \frac{7}{9} \\ \\ \\ = > \frac{7}{9} = \frac{7}{9} \\ \\ \\ = > 0 = 0$

hence proved!

To find:-

• Equivalent fraction with denominator 108.

Solution:-

• $= > 108 \div denominator \\ \\ \\ = > 108 \div 9 \\ \\ \\ = > 12 \\ \\ \\ = > \frac{7 \times 12}{9 \times 12} \\ \\ \\ = > \frac{84}{108}$
• The fraction is 84/108.

Varifying:-

• $= > \frac{84 \div 7}{108 \div 9} \: \: = \: \: \frac{7}{9} \\ \\ \\ = > \frac{7}{9} = \frac{7}{9} \\ \\ \\ = > 0 = 0$

hence proved!

Hope it helped!

Answer 2

Step-by-step explanation:

1)56/72

2)84/108

Thank you...❤️