Question

Find the equivalent resistance????​

Answer 1

Answer:

for figure A, 8Ω

and for figure B, also, 8Ω

Explanation:

for figure A

1/(1/8+1/16+1/16)=4Ω(method of finding equivalent resistances in parallel combination)

20Ω+4Ω=24Ω (method of finding equivalent resistances in series combination)

now,

1/(1/9+1/18)=6Ω(method of finding equivalent resistances in parallel combination)

6Ω+6ΩΩ=12(method of finding equivalent resistances in series combination)

now final resistance is,

R=1(1/24+1/12)=8Ω(method of finding equivalent resistances in parallel combination) is the answer

for figure B

shift point A on the line segment DE and bend the corner E to straighten it, as it is a wire now as in previous figure,

1/(1/10+1/2.5)=2Ω(method of finding equivalent resistances in parallel combination)

2Ω+10Ω=12Ω(method of finding equivalent resistances in series combination)

1/(1/12+1/12)=6Ω(method of finding equivalent resistances in parallel combination)

6Ω+10Ω=16Ω(method of finding equivalent resistances in series combination)

now the final resistance is,

R=1/(1/16+1/16)=8Ω(method of finding equivalent resistances in parallel combination)