Question

find the equivalent resistance across a and b where r1=r2=r3=r4=r5=r6=r7=r8=2ohm​

Answer 1

Answer:

are they in series or parraral

Answer 2

Answer:

Given:

please find in attachment.

To prove:

Resistance equal between two circuit-endings A and B= ?

Solution:

$∴ R_1 and \: R_2$

1Rb and R2

R1 and R2. are parallel:

$\begin{gathered} < /p > < p > {\begin{gathered}{\frac{1}{R'}=\frac{1}{R_1}+\frac{1}{R_2}\\\\ \frac{1}{R'}= \frac{1}{2}+\frac{1}{2}\\\\ \frac{1}{R'}=\frac{1+1}{2}\\\\\frac{1}{R'}=\frac{2}{2}\\\\}{R'}=1 \ ohm\\\end{gathered}}}\end{gathered}$

if in R'' (R_3 and R_4 were also parallel) then it will be : 1 ohm

Now calculate R' and R'':

Where R' = 1 ohm and R''=1 ohm

Formula: R'+R'' = 1+1= 2 ohm

When we calculate the other R''' and R'''' So, they are also in parallel:

So, the total R =1 ohm.

The final answer is 1 ohm.

Explanation:

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