Question

Find the equivalent resistance across the two ends A and B of the given circuit. ​

Answer 1

Answer:

Hi

Explanation:

I am having the same question kindly write your answer fast as ai

Answer 2

Given:

$R_1 = 1\Omega \\\\R_2 =4\Omega\\\\R_3 = 2\Omega\\\\R_4=4\Omega\\\\R_5=1\Omega\\\\R_6=2\Omega\\\\R_7=2\Omega$

To find:

Total resistance

Solution:

$R_2$ and $R_3$ are in parallel,

$\frac{1}{R_2_3}= \frac{1}{R_2}+\frac{1}{R_3}$

Therefore $R_2_3 = 0.75$ $\Omega$

$R_1 , R_2_3, R_4 , R_5$are in series :

Therefore adding them : $R_1_2_3_4_5 = 5.33\Omega$

$R_6 , R_7$ are also in series , therefore:

$R_6_7 = R_6+R_7 = 4\Omega$

$R_1_2_3_4_5$  and $R_6_7$ are parallel to eachother, therefore:

Resultant $1/R = 0.187 + 0.25 =$$0.437$

$R= 2.28\Omega$

Hence answer should be 2.28 ohms