find the equivalent resistance across the two ends A and B in the following circuits
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1
R=R1,+R2+R3+R4+R5 to find out this formula
Answered by
5
Since they are connected in series
R= R1+R2+R3+R4+R5
R=R+R+R+R+R
R=5R
R= R1+R2+R3+R4+R5
R=R+R+R+R+R
R=5R
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