Question

find the equivalent resistance across the two ends a and b of the following circuit

Answer 1

Hey Mate

your answer is ---

equivalent resistance is --

1/R = 1/5+1/10+1/5

=> 1/R = 2+1+2/10

=> 1/R = 5/10

=> R = 10/5

=> R = 2ohm

hence, equivalent resistance is 2ohm



hope it help you

Answer 2

Yeah sure for your help
********************
®®®®®®®®®®®®®®®
Here is your answer which you are searching for
✍✍

♦ In between of the circuit you see 5 Omega and 5 Omega are connected in series

♦ In series we use the formula Rs = R1+R2 ......Rn

♦ Resistance in series = 5 + 5 = 10 Omega

♦ Now you see Resistance are connected in parallel means that it have connected with two ends of the circuit

♦ Formula for Resistance in parallel is 1/R1 +1/R2...........1/R/n

♦ 1/R = 1/5+ 1/10+ 1/5

♦ When we calculate this our answer becomes 2omega

♦ 2 Omega is the answer of your question
*********************
®®®®®®®®®®®®®®®®®
✍✍

Be Brainly
Be Proud
Together we can change the world ❤
<< Warm Regards
@ Brainlestuser