Question

find the equivalent resistance across the two ends A and B of the following circuit

Answer 1

ans is 2 ohm

1+2+1=4 at top  ,bottom 4 ohm  4 and and parallel  ans 2ohm

Answer 2

Answer:

The equivalent resistance across the two ends A and B of the above circuit is 2Ω.

Explanation:

Let the resistors in the upper traingle be R1=4Ω, R2=2Ω and R3=2Ω.

So, the equivalent resistance in the upper triangle is,

Req1 = (R1x(R2+R3))/(R1+R2+R3)Ω

        = (4x(2+2))/(4+2+2)Ω

        = 2Ω

Let the resistors in the upper branch be R4=1Ω, R5=1Ω and in the lower branch R6=2Ω, r7=2Ω.

So, the series resistance in the upper branch is,

Rs1 = R4 + R5 + Req1

     = 1 + 1 + 2

     = 4Ω

So, the series resistance in the lower branch is,

Rs2 = R6 + R7

     = 2 + 2

     = 4Ω

So, the equivalent resistance across the two ends A and B of the above  circuit is,

Req2 = (Rs1 x Rs2)/(Rs1 + Rs2)

          = (4 x 4)/(4+4)

          = 16/8

          = 2Ω