Question

find the equivalent resistance across two ends A and B of the circuit ( all the resistance are 2 ohm)

Answer 1

Hope it helps you dear....

Answer 2

Given:

please find in attachment.

To prove:

Resistance equal between two circuit-endings A and B= ?

Solution:

$\Therefore$$\therefore$ $R_1 \ and R_2$ are parallel:

$\frac{1}{R'}=\frac{1}{R_1}+\frac{1}{R_2}\\\\ \frac{1}{R'}= \frac{1}{2}+\frac{1}{2}\\\\ \frac{1}{R'}=\frac{1+1}{2}\\\\\frac{1}{R'}=\frac{2}{2}\\\\}{R'}=1 \ ohm$

if in R'' (R_3 and R_4 were also parallel) then it will be : 1 ohm

Now calculate R' and R'':

Where R' = 1 ohm and R''=1 ohm

Formula: R'+R'' = 1+1= 2 ohm

When we calculate the other R''' and R'''' So, they are also in parallel:

So, the total R =1 ohm.

The final answer is 1 ohm.