Question

find the equivalent resistance and current flowing in the given circuit​

Answer 1

Given

• R₁ =4 Ω
• R₂=6Ω
• R₃=3Ω
• V= 24 volt

To find

• To find equivalent resistance
• current

Concept-

ohms law and combination of resistance

Solution

In the given problem the resistor R₂ and R₃ are parallel and R₁ is in series with R₂ and R₃.

let's calculate the resistance in parallel combination

$\sf{\to\frac{1}{R_{parallel}} =\frac{1}{R_{2}} +\frac{1}{R_{3}} }$

$\sf{\to\frac{1}{R_{parallel}} =\frac{1}{6} +\frac{1}{4} }$

$\sf{\to\frac{1}{R}_{parallel} =\frac{10}{24} } \\ \\ \sf{\to R_{parallel} =2.4 Ω }$

Now let us calculate the series resistance

$\sf{\to R_{eq}= 4 +2.4}\\\\\sf{\to R_{eq}=6.4 Ω}$

So the total Resistance of the circuit is 6.4 Ω.

We know that

$\bold{ V=IR}$

where

• v denotes voltage
• I denotes current
• R denotes resistance

$\sf{\to I=\frac{V}{R} }$

$\sf{\to I=\frac{24}{6.4} =\red{3.75 A}}$  

therefore the current in the circuit is 3.75 ampere.

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