find the equivalent resistance and total current in the circuit A series parallel combination circuit R2 = 20Ω R3 = 30Ω R4 = 40Ω R5 = 10Ω 12V
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>>If in figure R1 = 10Ω , R2 = 40Ω , R3 =
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If in figure R
1
=10Ω, R
2
=40Ω, R
3
=30Ω, R
4
=20Ω, R
5
=60Ω, and a 12 V battery is connected to the arrangement. Calculate (a) the total resistance in the circuit, and (b) the total current flowing in the circuit.
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(a) 10 ohm and 40 ohm are in parallel, so their equivalent resistance is
R
eq1
1
=
10
1
+
40
1
Gives, R
eq1
=8Ω
30ohm, 20ohm, 60ohm are in parallel
∴
R
eq2
1
=
30
1
+
20
1
+
60
1
=
60
2+3+1
=
10
1
∴R
eq2
=10Ω
Now R
eq1
and R
eq2
are in series.
Total resistance of the circuit R=R
eq1
+R
eq2
=8+10=18Ω
(b) Total current=
R
V
=
18
12
=0.67A
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